Talia Gibson defeated Ekaterina Alexandrova 6-3 7-5 in the Indian Wells round of 64 on hard. The upset overturned the form book — Ekaterina Alexandrova came in ranked #18, leading the head-to-head 1–0, defending last year's round of 64. Talia Gibson claimed a first win over Ekaterina Alexandrova in two meetings, narrowing the head-to-head to 1–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2026-08-06 | Toronto | R32 | hard | Ekaterina Alexandrova | 7-5 1-6 3-6 |
Averages over each player's completed matches in the selected window (46 vs 25). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Gibson T.: 4 days rest · 2 matches, 50 games (7d) · Alexandrova E.: 2 days rest · 2 matches, 60 games (7d). Higher means fresher. About
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About