Tatiana Panova vs Jelena Jankovic — Philadelphia Round of 32
Philadelphia · WTA · Round of 32
2 — 1
Sets
Monday, 31 October 2005 ·
carpet
Panova T.6-4 3-6 7-5
Jankovic J.
Panova T.
6372
Jankovic J.
4651
Tatiana Panova defeated Jelena Jankovic 6-4 3-6 7-5 in the Philadelphia round of 32 on carpet. The result followed the form book — Tatiana Panova came in leading the head-to-head 1–0, defending last year's round of 32. Tatiana Panova extended the head-to-head to 2–0.
Key context
- Match story: Tatiana Panova closed it out in three sets, 6–4 3–6 7–5.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-01-17 | Australian Open | R64 | hard | Tatiana Panova | 3-6 6-4 6-2 |
Statistics
This season1st serve in·Even
62%
62%
1st serve points won·Slight edge
54%
64%
2nd serve points won·Slight edge
38%
46%
Service points won·Slight edge
48%
57%
Return points won·Even
42%
45%
Break points saved·Even
51%
55%
Aces / match·Clear edge
0.7
2.9
Double faults / match·Dominant
6.1
3.8
Averages over each player's completed matches in the selected window (9 vs 200). ATP, WTA & Challenger.