Tatiana Panova vs Jelena Jankovic — Australian Open Round of 64
Australian Open · WTA · Round of 64
2 — 1
Sets
Monday, 17 January 2005 ·
hard
Panova T.3-6 6-4 6-2
Jankovic J.
Panova T.
3662
Jankovic J.
6421
Tatiana Panova defeated Jelena Jankovic 3-6 6-4 6-2 in the Australian Open round of 64 on hard. The result followed the form book — Tatiana Panova came in leading the head-to-head 1–0, defending last year's round of 128. Tatiana Panova extended the head-to-head to 2–0.
Key context
- Match story: Tatiana Panova dropped the opening set before beating Jelena Jankovic 3–6 6–4 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-10-31 | Philadelphia | R32 | carpet | Tatiana Panova | 6-4 3-6 7-5 |
Statistics
This season1st serve in·Even
61%
62%
1st serve points won·Slight edge
53%
64%
2nd serve points won·Slight edge
39%
46%
Service points won·Slight edge
48%
57%
Return points won·Even
41%
45%
Break points saved·Slight edge
48%
55%
Aces / match·Clear edge
0.8
2.9
Double faults / match·Dominant
6.6
3.8
Averages over each player's completed matches in the selected window (8 vs 200). ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast