Tatiana Panova vs Alexandra Stevenson — Rome Round of 64
Rome · WTA · Round of 64
2 — 0
Sets
Monday, 15 May 2000 ·
clay
Panova T.6-0 6-2
Stevenson A.
Panova T.
662
Stevenson A.
020
Tatiana Panova defeated Alexandra Stevenson 6-0 6-2 in the Rome round of 64 on clay. The upset overturned the form book — Alexandra Stevenson came in leading the head-to-head 2–0. Tatiana Panova claimed a first win over Alexandra Stevenson in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Tatiana Panova handed Alexandra Stevenson a first-set bagel in a 6–0 6–2 win.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-05-08 | Berlin | R64 | grass | Alexandra Stevenson | 6-2 7-6(2) |
| 1999-02-22 | Oklahoma | R16 | hard | Alexandra Stevenson | 2-6 7-6 7-5 |
Statistics
This season1st serve in·Even
61%
57%
1st serve points won·Clear edge
54%
66%
2nd serve points won·Even
40%
40%
Service points won·Slight edge
49%
55%
Return points won·Even
40%
37%
Break points saved·Slight edge
51%
61%
Aces / match·Dominant
0.8
4.5
Double faults / match·Even
5.9
6.0
Averages over each player's completed matches in the selected window (12 vs 26). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast