Alexandra Stevenson vs Tatiana Panova — Oklahoma Round of 16
Oklahoma · WTA · Round of 16
2 — 1
Sets
Monday, 22 February 1999 ·
hard
Stevenson A.2-6 7-6 7-5
Panova T.
Stevenson A.
2772
Panova T.
6651
Alexandra Stevenson defeated Tatiana Panova 2-6 7-6 7-5 in the Oklahoma round of 16 on hard. The result followed the form book — Alexandra Stevenson came in defending last year's round of 32. Alexandra Stevenson extended the head-to-head to 2–1.
Key context
- Match story: Alexandra Stevenson dropped the opening set before beating Tatiana Panova 2–6 7–6 7–5.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-05-15 | Rome | R64 | clay | Tatiana Panova | 6-0 6-2 |
| 2000-05-08 | Berlin | R64 | grass | Alexandra Stevenson | 6-2 7-6(2) |
Statistics
This season1st serve in·Even
57%
61%
1st serve points won·Clear edge
66%
54%
2nd serve points won·Even
40%
40%
Service points won·Slight edge
55%
49%
Return points won·Even
37%
40%
Break points saved·Slight edge
61%
51%
Aces / match·Dominant
4.5
0.8
Double faults / match·Even
6.0
5.9
Averages over each player's completed matches in the selected window (26 vs 12). ATP, WTA & Challenger.