Tatiana Panova vs Francesca Lubiani — Australian Open Round of 128
Australian Open · WTA · Round of 128
2 — 0
Sets
Monday, 19 January 1998 ·
hard
Panova T.6-4 6-4
Lubiani F.
Panova T.
662
Lubiani F.
440
Tatiana Panova defeated Francesca Lubiani 6-4 6-4 in the Australian Open round of 128 on hard. The upset overturned the form book — Francesca Lubiani came in leading the head-to-head 2–0, defending last year's round of 64. Tatiana Panova claimed a first win over Francesca Lubiani in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Tatiana Panova edged a tight contest from start to finish — 6–4 6–4.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1997-08-11 | Canadian Open | R64 | hard | Francesca Lubiani | 6-2 7-6 |
| 1996-05-27 | Roland Garros | Q64 | clay | Francesca Lubiani | 6-1 6-4 |
Statistics
This season1st serve in·
61%
—
1st serve points won·
54%
—
2nd serve points won·
40%
—
Service points won·
49%
—
Return points won·
40%
—
Break points saved·
51%
—
Aces / match·
0.8
—
Double faults / match·
5.9
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast