Francesca Lubiani vs Tatiana Panova — Canadian Open Round of 64
Canadian Open · WTA · Round of 64
2 — 0
Sets
Monday, 11 August 1997 ·
hard
Lubiani F.6-2 7-6
Panova T.
Lubiani F.
672
Panova T.
260
Francesca Lubiani defeated Tatiana Panova 6-2 7-6 in the Canadian Open round of 64 on hard. Francesca Lubiani extended the head-to-head to 2–1.
Key context
- Match story: Francesca Lubiani closed it out in two sets, 6–2 7–6.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-01-19 | Australian Open | R128 | hard | Tatiana Panova | 6-4 6-4 |
| 1996-05-27 | Roland Garros | Q64 | clay | Francesca Lubiani | 6-1 6-4 |
Statistics
This season1st serve in·
—
61%
1st serve points won·
—
54%
2nd serve points won·
—
40%
Service points won·
—
49%
Return points won·
—
40%
Break points saved·
—
51%
Aces / match·
—
0.8
Double faults / match·
—
5.9
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.