Sean Cuenin vs Stefan Horia Haita — M25 Kursumlijska Banja 3 Final
Cuenin S.
Sean Cuenin won the M25 Kursumlijska Banja 3 final, defeating Stefan Horia Haita 2-6, 7-6, 7-6. Cuenin hit 10 aces and 6 double faults, winning 69% of first-serve points, while converting 20% of break points and securing 2 service breaks. Haita had 7 aces, 5 double faults, and 69% first-serve win percentage, converting 67% of break points and securing 4 service breaks.
Key context
- Match story: Sean Cuenin dropped the opening set before beating Stefan Horia Haita 2–6 7–6 7–6.
Head to head
No previous meetings on record.
Statistics
This seasonAverages over each player's completed matches in the selected window (21 vs 2). ATP, WTA & Challenger.
Win Probability
Pre-match · updated 07:50 UTC50–58%
58–67%
67–80%
80%+
Strong favourite · Cuenin S. heavily favoured
Calibrated model (out-of-sample validated). Probability is a statistical estimate, not a certainty. How it works.
Umpiry Score
Pre-matchThe Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Freshness
Recent loadCuenin S.: 1 day rest · 1 match, 21 games (7d) · Horia Haita S.: 16 days rest. Higher means fresher. About