
Ekaterina Alexandrova defeated Anna Blinkova in the Round of 64 at the Cincinnati hard-court tournament. The match ended with a score of 6-7, 6-4, 7-5 in favor of Alexandrova. Alexandrova hit 9 aces and committed 5 double faults, while converting 70 percent of her break points and winning 7 service breaks to Blinkova's 5.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2025-06-09 | s Hertogenbosch | R16 | grass | Ekaterina Alexandrova | 6-0 7-5 |
Averages over each player's completed matches in the selected window (37 vs 26). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Slight edge · Alexandrova E. narrowly ahead
Calibrated model · 65% favourite accuracy (2025–26, out-of-sample). Probability is a statistical estimate, not a certainty. How it works.
The Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Blinkova A.: 3 days rest · 4 matches, 103 games (7d) · Alexandrova E.: 1 day rest · 2 matches, 60 games (7d). Higher means fresher. About
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About