Viktorija Golubic defeated Kimberly Birrell in the Round of 128 at the Toronto tournament, winning 7-6, 6-4 on hard courts. Golubic served zero aces and committed one double fault, while Birrell served five aces and eight double faults. Golubic converted 50% of her break points and secured four service breaks, compared to Birrell's three service breaks and 43% break point conversion rate.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2025-03-05 | Indian Wells | R128 | hard | Kimberly Birrell | 6-4 6-4 |
| 2022-08-25 | US Open | Q64 | hard | Viktorija Golubic | 6-2 2-6 6-4 |
Averages over each player's completed matches in the selected window (39 vs 41). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Slight edge · Birrell K. narrowly ahead
Calibrated model · 65% favourite accuracy (2025–26, out-of-sample). Probability is a statistical estimate, not a certainty. How it works.
The Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Birrell K.: 6 days rest · 1 match, 16 games (7d) · Golubic V.: 3 days rest · 2 matches, 53 games (7d). Higher means fresher. About
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About