Jan Lennard Struff defeated Sebastian Baez in the Round of 128 at Wimbledon. The match ended with a score of 6-1, 7-6, 4-6, 2-6, 7-5. Struff served 20 aces and converted 44 percent of break points, while Baez had 4 aces and converted 33 percent of break points; both players won 4 service breaks.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2024-04-08 | Monte Carlo Masters | R64 | clay | Jan Lennard Struff | 1-6 7-6 6-2 |
Averages over each player's completed matches in the selected window (25 vs 35). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Toss-up · Too close to call
Calibrated model · 65% favourite accuracy (2025–26, out-of-sample). Probability is a statistical estimate, not a certainty. How it works.
The Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Lennard Struff J.: 4 days rest · 2 matches, 49 games (7d) · Baez S.: 3 days rest · 2 matches, 48 games (7d). Higher means fresher. About
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the grass field, opponent-adjusted over 52 weeks). About