Alec Beckley vs Thando Longwe Smit — Centurion 1 CH Qualifying Round 2
Centurion 1 CH · CHALLENGER · Qualifying Round 2
2 — 1
Sets
Monday, 25 May 2026 ·
hard
Beckley A.6-3 6-7 6-2
Longwe Smit T.
Beckley A.
6662
Longwe Smit T.
3721
Alec Beckley defeated Thando Longwe Smit 6-3 6-7 6-2 in the Centurion 1 CH qualifying round 2 on hard. The result followed the form book — Alec Beckley came in ranked #560, leading the head-to-head 2–0. Alec Beckley extended the head-to-head to 3–0.
Key context
- Match story: Alec Beckley closed it out in three sets, 6–3 6–7 6–2.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2024-12-10 | M15 Stellenbosch 2 | R32 | hard | Alec Beckley | 7-5 6-1 |
| 2024-12-05 | M15 Stellenbosch 1 | R16 | hard | Alec Beckley | 6-2 6-3 |
Statistics
This season1st serve in·Slight edge
63%
55%
1st serve points won·Slight edge
70%
80%
2nd serve points won·Slight edge
46%
52%
Service points won·Slight edge
61%
68%
Return points won·Slight edge
36%
47%
Break points saved·Dominant
58%
87%
Aces / match·Clear edge
2.0
4.0
Double faults / match·Even
3.2
3.5
Averages over each player's completed matches in the selected window (6 vs 2). ATP, WTA & Challenger.
Freshness
Recent loadFreshness·
83
—
Beckley A.: 3 days rest · 1 match, 31 games (7d). Higher means fresher. About