
Alexander Zverev defeated Pierre Hugues Herbert 2-6 6-4 7-6 4-6 6-4 in the Roland Garros round of 64 on clay. The result followed the form book — Alexander Zverev came in ranked #3, defending last year's quarter-final. Alexander Zverev narrowed the head-to-head to 2–2.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-05-23 | Roland Garros | R128 | clay | Alexander Zverev | 5-7 6-2 7-6 7-5 |
| 2015-01-04 | Brisbane | Q1 | hard | Pierre Hugues Herbert | 7-6 6-4 |
| 2013-09-16 | Metz | QF | hard | Pierre Hugues Herbert | 2-6 6-4 6-3 |
Averages over each player's completed matches in the selected window (199 vs 200). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Zverev A.: 5 days rest · 2 matches, 59 games (7d) · Hugues Herbert P.: 1 day rest · 2 matches, 60 games (7d). Higher means fresher. About
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the clay field, opponent-adjusted over 52 weeks). About