Henri Laaksonen vs Facundo Arguello — Roland Garros Q64
Roland Garros · ATP · Q64
2 — 1
Sets
Wednesday, 22 May 2019 ·
clay
Laaksonen H.4-6 6-4 6-3
Arguello F.
Laaksonen H.
4662
Arguello F.
6431
Henri Laaksonen defeated Facundo Arguello 4-6 6-4 6-3 in the Roland Garros q64 on clay. The result followed the form book — Henri Laaksonen came in leading the head-to-head 1–0. Henri Laaksonen extended the head-to-head to 2–0.
Key context
- Match story: Henri Laaksonen dropped the opening set before beating Facundo Arguello 4–6 6–4 6–3.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2019-05-27 | Roland Garros | Q2 | clay | Henri Laaksonen | 4-6 6-4 6-3 |
Statistics
This season1st serve in·Even
56%
59%
1st serve points won·Even
70%
66%
2nd serve points won·Even
49%
51%
Service points won·Even
61%
60%
Return points won·Even
38%
41%
Break points saved·Even
60%
59%
Aces / match·Dominant
5.6
2.3
Double faults / match·Even
2.8
2.7
Averages over each player's completed matches in the selected window (200 vs 50). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast