Radu Albot vs Jan Mertl — St. Petersburg Qualifying Round 2
St. Petersburg · CHALLENGER · Qualifying Round 2
2 — 0
Sets
Monday, 19 September 2016 ·
hard
Albot R.6-3 6-4
Mertl J.
Albot R.
662
Mertl J.
340
Radu Albot defeated Jan Mertl 6-3 6-4 in the St. Petersburg qualifying round 2 on hard. The result followed the form book — Radu Albot came in leading the head-to-head 2–0, defending last year's round of 32. Radu Albot extended the head-to-head to 3–0.
Key context
- Match story: Radu Albot closed it out in two sets, 6–3 6–4.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-01-18 | Australian Open | Q1 | hard | Radu Albot | 6-3 7-6 |
| 2016-01-13 | Australian Open | Q128 | hard | Radu Albot | 6-3 7-6(2) |
Statistics
This season1st serve in·Even
64%
63%
1st serve points won·Slight edge
66%
73%
2nd serve points won·Even
49%
50%
Service points won·Even
60%
64%
Return points won·Even
40%
38%
Break points saved·Even
60%
63%
Aces / match·Dominant
2.0
6.6
Double faults / match·Even
2.9
2.8
Averages over each player's completed matches in the selected window (199 vs 69). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast