Jose Rubin Statham vs Steven De Waard — Australia F3 Round of 32
Australia F3 · ITF · Round of 32
2 — 0
Sets
Monday, 14 March 2016 ·
clay
Rubin Statham J.6-4 6-2
De Waard S.
Rubin Statham J.
662
De Waard S.
420
Jose Rubin Statham defeated Steven De Waard 6-4 6-2 in the Australia F3 round of 32 on clay. The result followed the form book — Jose Rubin Statham came in leading the head-to-head 1–0. Jose Rubin Statham extended the head-to-head to 2–0.
Key context
- Match story: Jose Rubin Statham dropped just 6 games past Steven De Waard.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-04-04 | Australia F4 | R32 | clay | Jose Rubin Statham | 6-2 6-0 |
Statistics
This season1st serve in·Even
62%
62%
1st serve points won·Slight edge
72%
66%
2nd serve points won·Even
52%
50%
Service points won·Slight edge
65%
60%
Return points won·Even
36%
37%
Break points saved·Even
59%
58%
Aces / match·Clear edge
6.2
3.5
Double faults / match·Slight edge
2.8
3.2
Averages over each player's completed matches in the selected window (200 vs 37). ATP, WTA & Challenger.