Scott Griekspoor vs Yannik ReuterNetherlands F2 Final

Netherlands F2 · ITF · Final
35 yrs · Right-handed
Last 10 · pre-match
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2 — 0
Sets
Monday, 22 June 2015 ·
clay
35 yrs · Right-handed
Last 10 · pre-match
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Griekspoor S.
6-4 6-1
Reuter Y.
Griekspoor S.
662
Reuter Y.
410

Scott Griekspoor defeated Yannik Reuter 6-4 6-1 in the Netherlands F2 final on clay.

Key context

Head to head

No previous meetings on record.

Statistics

This season
1st serve in·Even
62%
60%
1st serve points won·Even
70%
67%
2nd serve points won·Even
50%
49%
Service points won·Even
62%
59%
Return points won·Even
37%
40%
Break points saved·Slight edge
64%
54%
Aces / match·Clear edge
4.8
2.3
Double faults / match·Clear edge
3.9
2.6

Averages over each player's completed matches in the selected window (111 vs 126). ATP, WTA & Challenger.

Draw