Quentin Robert (1994) vs Arthur Surreaux — Greece F6 Round of 32

Greece F6 · ITF · Round of 32
FRA
Quentin Robert (1994)
31 yrs
Last 10 · pre-match
LLLWLLLLWL
2 — 0
Sets
Monday, 27 April 2015 ·
hard
FRA
Arthur Surreaux
39 yrs · Right-handed
Last 10 · pre-match
LLLLLLLLLL
Robert (1994) Q.
7-5 7-5
Surreaux A.
Robert (1994) Q.
772
Surreaux A.
550

Quentin Robert (1994) defeated Arthur Surreaux 7-5 7-5 in the Greece F6 round of 32 on hard.

Key context

  • Match story: Quentin Robert (1994) edged Arthur Surreaux in two tight sets (7–5 7–5).

Head to head

No previous meetings on record.

Statistics

This season
Robert (1994) Q.Surreaux A.
1st serve in·Slight edge
56%
65%
1st serve points won·Clear edge
70%
53%
2nd serve points won·Clear edge
46%
31%
Service points won·Clear edge
60%
46%
Return points won·Even
43%
39%
Break points saved·Clear edge
56%
43%
Aces / match·Clear edge
3.5
0.8
Double faults / match·Clear edge
5.1
3.8

Averages over each player's completed matches in the selected window (99 vs 4). ATP, WTA & Challenger.

Draw