Jelena Jankovic vs Yvonne Meusburger — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 0
Sets
Monday, 3 March 2014 ·
hard
Jankovic J.6-3 6-1
Meusburger Y.
Jankovic J.
662
Meusburger Y.
310
Jelena Jankovic defeated Yvonne Meusburger 6-3 6-1 in the Indian Wells round of 64 on hard. The result followed the form book — Jelena Jankovic came in leading the head-to-head 1–0, defending last year's round of 64. Jelena Jankovic extended the head-to-head to 2–0.
Key context
- Match story: Jelena Jankovic dropped just 4 games past Yvonne Meusburger.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2009-01-19 | Australian Open | R128 | hard | Jelena Jankovic | 6-1 6-3 |
Statistics
This season1st serve in·Slight edge
63%
69%
1st serve points won·Slight edge
64%
56%
2nd serve points won·Slight edge
46%
39%
Service points won·Slight edge
58%
51%
Return points won·Even
44%
46%
Break points saved·Slight edge
57%
47%
Aces / match·Clear edge
3.0
1.0
Double faults / match·Even
3.7
4.0
Averages over each player's completed matches in the selected window (167 vs 30). ATP, WTA & Challenger.
Clutch
Under pressureClutch Rating·Clear edge
52
40
Break points saved·Dominant
46
21
Break points won·Clear edge
97
78
Deciding sets·Even
46
47
Tiebreaks·Clear edge
56
72
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Conditions
Court speed
Medium-slowfavours grinders
SlowFast