Yannick Mertens vs Mathieu Rodrigues — France F4 Final
France F4 · ITF · Final
2 — 0
Sets
Monday, 24 February 2014 ·
hard
Mertens Y.6-2 6-1
Rodrigues M.
Mertens Y.
662
Rodrigues M.
210
Yannick Mertens defeated Mathieu Rodrigues 6-2 6-1 in the France F4 final on hard. The result followed the form book — Yannick Mertens came in leading the head-to-head 3–0. Yannick Mertens extended the head-to-head to 4–0.
Key context
- Match story: Yannick Mertens dropped just 3 games past Mathieu Rodrigues.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-10-21 | France F21 | R16 | hard | Yannick Mertens | 6-0 7-6(1) |
| 2009-10-19 | Great Britain F15 | SF | hard | Yannick Mertens | 6-2 7-5 |
| 2008-11-03 | Spain F42 | QF | hard | Yannick Mertens | 7-5 6-3 |
Statistics
This season1st serve in·Slight edge
65%
55%
1st serve points won·Even
68%
72%
2nd serve points won·Even
51%
49%
Service points won·Even
62%
62%
Return points won·Even
39%
36%
Break points saved·Even
59%
55%
Aces / match·Clear edge
2.7
4.5
Double faults / match·Slight edge
2.8
2.2
Averages over each player's completed matches in the selected window (200 vs 10). ATP, WTA & Challenger.