Wesley Koolhof vs Alexandre Sidorenko — Netherlands F5 Round of 16
Netherlands F5 · ITF · Round of 16
2 — 0
Sets
Monday, 19 August 2013 ·
clay
Koolhof W.6-2 7-5
Sidorenko A.
Koolhof W.
672
Sidorenko A.
250
Wesley Koolhof defeated Alexandre Sidorenko 6-2 7-5 in the Netherlands F5 round of 16 on clay. The upset overturned the form book — Alexandre Sidorenko came in leading the head-to-head 2–0. Wesley Koolhof claimed a first win over Alexandre Sidorenko in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Wesley Koolhof closed it out in two sets, 6–2 7–5.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-03-04 | Israel F5 | R32 | hard | Alexandre Sidorenko | 2-6 6-1 6-3 |
| 2011-08-29 | Netherlands F6 | QF | clay | Alexandre Sidorenko | 6-3 6-3 |
Statistics
This season1st serve in·Even
58%
56%
1st serve points won·Slight edge
67%
74%
2nd serve points won·Even
50%
48%
Service points won·Even
60%
62%
Return points won·Even
37%
37%
Break points saved·Even
57%
57%
Aces / match·Dominant
2.8
5.9
Double faults / match·Dominant
2.0
4.4
Averages over each player's completed matches in the selected window (11 vs 61). ATP, WTA & Challenger.