Lukasz Kubot vs Florent Serra — Roland Garros Round of 64
Roland Garros · ATP · Round of 64
3 — 0
Sets
Sunday, 27 May 2012 ·
clay
Kubot L.7-6 6-2 7-6
Serra F.
Kubot L.
7673
Serra F.
6260
Lukasz Kubot defeated Florent Serra 7-6 6-2 7-6 in the Roland Garros round of 64 on clay. The upset overturned the form book — Florent Serra came in leading the head-to-head 1–0, defending last year's round of 128. Lukasz Kubot claimed a first win over Florent Serra in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Lukasz Kubot closed it out in three sets, 7–6 6–2 7–6.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2002-08-26 | Netherlands F2 | R32 | clay | Florent Serra | 7-5 2-6 6-4 |
Statistics
This season1st serve in·Even
61%
59%
1st serve points won·Even
69%
68%
2nd serve points won·Even
48%
51%
Service points won·Even
61%
61%
Return points won·Even
36%
35%
Break points saved·Even
59%
57%
Aces / match·Clear edge
5.7
3.4
Double faults / match·Dominant
4.8
1.7
Averages over each player's completed matches in the selected window (97 vs 37). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast