Alexandros Jakupovic vs Yannick Jankovits — Greece F2 Semi-final
Greece F2 · ITF · Semi-final
2 — 0
Sets
Monday, 9 April 2012 ·
carpet
Jakupovic A.7-6 7-6
Jankovits Y.
Jakupovic A.
77772
Jankovits Y.
63640
Alexandros Jakupovic defeated Yannick Jankovits 7-6 7-6 in the Greece F2 semi-final on carpet. The result followed the form book — Alexandros Jakupovic came in leading the head-to-head 2–0. Alexandros Jakupovic extended the head-to-head to 3–0.
Key context
- Match story: Alexandros Jakupovic won all two sets in tiebreaks against Yannick Jankovits.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-04-08 | Greece F2 | R16 | hard | Alexandros Jakupovic | 6-1 6-2 |
| 2012-11-05 | Greece F6 | QF | carpet | Alexandros Jakupovic | 6-4 1-6 7-6(3) |
Statistics
This season1st serve in·
—
57%
1st serve points won·
—
69%
2nd serve points won·
—
50%
Service points won·
—
61%
Return points won·
—
42%
Break points saved·
—
57%
Aces / match·
—
2.9
Double faults / match·
—
2.8
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.