Giulio Torroni vs Yannik Reuter — Romania F1 Round of 32
Romania F1 · ITF · Round of 32
2 — 0
Sets
Monday, 23 May 2011 ·
clay
Torroni G.6-3 7-5
Reuter Y.
Torroni G.
672
Reuter Y.
350
Giulio Torroni defeated Yannik Reuter 6-3 7-5 in the Romania F1 round of 32 on clay. The result followed the form book — Giulio Torroni came in leading the head-to-head 1–0. Giulio Torroni extended the head-to-head to 2–0.
Key context
- Match story: Giulio Torroni closed it out in two sets, 6–3 7–5.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-06-23 | Italy F20 | R16 | clay | Giulio Torroni | 6-4 6-3 |
Statistics
This season1st serve in·Even
63%
61%
1st serve points won·Even
64%
66%
2nd serve points won·Clear edge
35%
49%
Service points won·Slight edge
53%
59%
Return points won·Even
39%
40%
Break points saved·Even
50%
54%
Aces / match·Clear edge
0.0
2.3
Double faults / match·Slight edge
3.0
2.5
Averages over each player's completed matches in the selected window (1 vs 143). ATP, WTA & Challenger.