Jose Rubin Statham vs Steven De Waard — Australia F4 Round of 32
Australia F4 · ITF · Round of 32
2 — 0
Sets
Monday, 4 April 2011 ·
clay
Rubin Statham J.6-2 6-0
De Waard S.
Rubin Statham J.
662
De Waard S.
200
Jose Rubin Statham defeated Steven De Waard 6-2 6-0 in the Australia F4 round of 32 on clay. The result followed the form book — Jose Rubin Statham came in leading the head-to-head 1–0. Jose Rubin Statham extended the head-to-head to 2–0.
Key context
- Match story: Jose Rubin Statham handed Steven De Waard a second-set bagel in a 6–2 6–0 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-03-14 | Australia F3 | R32 | clay | Jose Rubin Statham | 6-4 6-2 |
Statistics
This season1st serve in·Even
62%
61%
1st serve points won·Slight edge
72%
66%
2nd serve points won·Even
52%
50%
Service points won·Slight edge
65%
60%
Return points won·Even
36%
37%
Break points saved·Even
59%
58%
Aces / match·Clear edge
6.2
3.4
Double faults / match·Slight edge
2.8
3.2
Averages over each player's completed matches in the selected window (200 vs 38). ATP, WTA & Challenger.