Alexandros Jakupovic vs Daniel Glancy — Greece F3 Round of 16
Greece F3 · ITF · Round of 16
2 — 0
Sets
Monday, 25 October 2010 ·
carpet
Jakupovic A.6-4 6-1
Glancy D.
Jakupovic A.
662
Glancy D.
410
Alexandros Jakupovic defeated Daniel Glancy 6-4 6-1 in the Greece F3 round of 16 on carpet. The result followed the form book — Alexandros Jakupovic came in leading the head-to-head 1–0. Alexandros Jakupovic extended the head-to-head to 2–0.
Key context
- Match story: Alexandros Jakupovic dropped just 5 games past Daniel Glancy.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-10-11 | Greece F1 | R16 | hard | Alexandros Jakupovic | 2-6 6-4 6-4 |
Statistics
This season1st serve in·
—
59%
1st serve points won·
—
60%
2nd serve points won·
—
45%
Service points won·
—
54%
Return points won·
—
34%
Break points saved·
—
51%
Aces / match·
—
1.8
Double faults / match·
—
3.5
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.