Isaac Frost vs Jose Rubin Statham — Australia F9 Round of 16
Australia F9 · ITF · Round of 16
2 — 1
Sets
Monday, 11 October 2010 ·
hard
Frost I.5-7 6-4 6-4
Rubin Statham J.
Frost I.
5662
Rubin Statham J.
7441
Isaac Frost defeated Jose Rubin Statham 5-7 6-4 6-4 in the Australia F9 round of 16 on hard. The upset overturned the form book — Jose Rubin Statham came in leading the head-to-head 1–0, but Isaac Frost had been the form player, winning 3 of their last 7 on hard. Isaac Frost claimed a first win over Jose Rubin Statham in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Isaac Frost dropped the opening set before beating Jose Rubin Statham 5–7 6–4 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2009-09-21 | Australia F6 | R16 | hard | Jose Rubin Statham | 6-2 6-1 |
Statistics
This season1st serve in·Slight edge
53%
62%
1st serve points won·Slight edge
77%
72%
2nd serve points won·Even
50%
52%
Service points won·Even
64%
65%
Return points won·Even
35%
36%
Break points saved·Even
59%
59%
Aces / match·Clear edge
8.4
6.2
Double faults / match·Clear edge
3.7
2.8
Averages over each player's completed matches in the selected window (7 vs 200). ATP, WTA & Challenger.