Jakob Sude vs Yannick Jankovits — France F16 Round of 32
France F16 · ITF · Round of 32
2 — 0
Sets
Monday, 27 September 2010 ·
carpet
Sude J.6-3 7-6
Jankovits Y.
Sude J.
6772
Jankovits Y.
3640
Jakob Sude defeated Yannick Jankovits 6-3 7-6 in the France F16 round of 32 on carpet. The upset overturned the form book — Yannick Jankovits came in leading the head-to-head 2–0. Jakob Sude claimed a first win over Yannick Jankovits in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Jakob Sude closed it out in two sets, 6–3 7–6.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2017-11-20 | Greece F10 | QF | hard | Yannick Jankovits | 6-3 6-3 |
| 2017-02-27 | Italy F2 | R16 | carpet | Yannick Jankovits | 7-6(4) 6-3 |
Statistics
This season1st serve in·Slight edge
64%
57%
1st serve points won·Even
69%
69%
2nd serve points won·Even
48%
50%
Service points won·Even
61%
61%
Return points won·Even
38%
42%
Break points saved·Even
58%
57%
Aces / match·Slight edge
4.1
2.9
Double faults / match·Slight edge
2.4
2.8
Averages over each player's completed matches in the selected window (48 vs 109). ATP, WTA & Challenger.