Radu Albot vs Andrei Ciumac — Belarus F2 Round of 32
Belarus F2 · ITF · Round of 32
2 — 1
Sets
Monday, 16 August 2010 ·
clay
Albot R.5-7 6-1 7-6
Ciumac A.
Albot R.
56772
Ciumac A.
71631
Radu Albot defeated Andrei Ciumac 5-7 6-1 7-6 in the Belarus F2 round of 32 on clay. The result followed the form book — Radu Albot came in leading the head-to-head 2–0. Radu Albot extended the head-to-head to 3–0.
Key context
- Match story: Radu Albot dropped the opening set before beating Andrei Ciumac 5–7 6–1 7–6.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-04-15 | Turkey F15 | R16 | hard | Radu Albot | 6-3 6-7(5) 7-5 |
| 2012-04-23 | Turkey F16 | R16 | hard | Radu Albot | 7-6(5) 6-2 |
Statistics
This season1st serve in·Even
64%
61%
1st serve points won·Slight edge
66%
57%
2nd serve points won·Slight edge
49%
39%
Service points won·Slight edge
60%
50%
Return points won·Even
40%
40%
Break points saved·Even
60%
58%
Aces / match·Slight edge
2.0
3.3
Double faults / match·Even
2.9
3.0
Averages over each player's completed matches in the selected window (199 vs 3). ATP, WTA & Challenger.