Florian Reynet vs Talal Ouahabi — Morocco F4 Round of 16
Morocco F4 · ITF · Round of 16
2 — 0
Sets
Monday, 21 June 2010 ·
clay
Reynet F.6-0 6-3
Ouahabi T.
Reynet F.
662
Ouahabi T.
030
Florian Reynet defeated Talal Ouahabi 6-0 6-3 in the Morocco F4 round of 16 on clay. The result followed the form book — Florian Reynet came in leading the head-to-head 1–0. Florian Reynet extended the head-to-head to 2–0.
Key context
- Match story: Florian Reynet handed Talal Ouahabi a first-set bagel in a 6–0 6–3 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-10-10 | Morocco F8 | R16 | clay | Florian Reynet | 6-1 6-1 |
Statistics
This season1st serve in·
57%
—
1st serve points won·
63%
—
2nd serve points won·
46%
—
Service points won·
56%
—
Return points won·
38%
—
Break points saved·
48%
—
Aces / match·
3.0
—
Double faults / match·
3.7
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.