Yannick Mertens vs Pierre Hugues Herbert — France F4 Qualifying Round
France F4 · ITF · Qualifying Round
2 — 0
Sets
Monday, 8 March 2010 ·
hard
#287ATP
1607ELO
1577Hard ELO
35 yrs · 188 cm · Right-handed
Last 10 · pre-match
LLWLLLLLWW
Mertens Y.7-5 6-2
Hugues Herbert P.
Mertens Y.
762
Hugues Herbert P.
520
Yannick Mertens defeated Pierre Hugues Herbert 7-5 6-2 in the France F4 qualifying round on hard. The result followed the form book — Yannick Mertens came in leading the head-to-head 2–0. Yannick Mertens extended the head-to-head to 3–0.
Key context
- Match story: Yannick Mertens closed it out in two sets, 7–5 6–2.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-06-06 | Netherlands F1 | R16 | clay | Yannick Mertens | 6-3 5-7 6-3 |
| 2011-02-12 | Marseille | Q32 | hard | Yannick Mertens | 6-4 1-6 7-5 |
Statistics
This season1st serve in·Slight edge
65%
60%
1st serve points won·Slight edge
68%
75%
2nd serve points won·Even
51%
49%
Service points won·Even
62%
65%
Return points won·Even
39%
35%
Break points saved·Even
59%
63%
Aces / match·Dominant
2.7
8.3
Double faults / match·Dominant
2.8
5.0
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Freshness
Recent loadFreshness·
—
61
Hugues Herbert P.: 1 day rest · 2 matches, 60 games (7d). Higher means fresher. About