Ruben Bemelmans vs Yannick Mertens — France F4 Semi-final
France F4 · ITF · Semi-final
2 — 0
Sets
Monday, 8 March 2010 ·
hard
Bemelmans R.7-6 7-6
Mertens Y.
Bemelmans R.
78772
Mertens Y.
66600
Ruben Bemelmans defeated Yannick Mertens 7-6 7-6 in the France F4 semi-final on hard. The result followed the form book — Ruben Bemelmans came in leading the head-to-head 1–0. Ruben Bemelmans extended the head-to-head to 2–0.
Key context
- Match story: Ruben Bemelmans won all two sets in tiebreaks against Yannick Mertens.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-07-11 | Belgium F5 | F | hard | Ruben Bemelmans | 6-3 6-7(3) 6-1 |
Statistics
This season1st serve in·Even
64%
65%
1st serve points won·Even
71%
68%
2nd serve points won·Even
52%
51%
Service points won·Even
64%
62%
Return points won·Even
37%
39%
Break points saved·Even
61%
59%
Aces / match·Clear edge
5.6
2.7
Double faults / match·Even
2.6
2.8
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.