Razvan Sabau vs Florian Reynet — Romania F13 Round of 16
Romania F13 · ITF · Round of 16
2 — 0
Sets
Monday, 21 July 2008 ·
clay
Sabau R.7-5 6-4
Reynet F.
Sabau R.
762
Reynet F.
540
Razvan Sabau defeated Florian Reynet 7-5 6-4 in the Romania F13 round of 16 on clay. The upset overturned the form book — Florian Reynet came in leading the head-to-head 1–0. Razvan Sabau claimed a first win over Florian Reynet in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Razvan Sabau edged Florian Reynet in two tight sets (7–5 6–4).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-05-31 | Romania F3 | SF | clay | Florian Reynet | 0-6 7-5 6-1 |
Statistics
This season1st serve in·
—
57%
1st serve points won·
—
63%
2nd serve points won·
—
46%
Service points won·
—
56%
Return points won·
—
38%
Break points saved·
—
48%
Aces / match·
—
3.0
Double faults / match·
—
3.7
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.