Paul Henri Mathieu vs Victor Hanescu — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 0
Sets
Monday, 14 January 2008 ·
hard
Henri Mathieu P.6-1 7-6 6-2
Hanescu V.
Henri Mathieu P.
6763
Hanescu V.
1620
Paul Henri Mathieu defeated Victor Hanescu 6-1 7-6 6-2 in the Australian Open round of 128 on hard. The result followed the form book — Paul Henri Mathieu came in leading the head-to-head 1–0, defending last year's round of 128. Paul Henri Mathieu extended the head-to-head to 2–0.
Key context
- Match story: Paul Henri Mathieu came through a tight passage before pulling clear — 6–1 7–6 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-08-15 | Cincinnati Masters | R64 | hard | Paul Henri Mathieu | 6-7 7-6 6-3 |
Statistics
This season1st serve in·Clear edge
56%
70%
1st serve points won·Even
71%
69%
2nd serve points won·Even
50%
50%
Service points won·Even
62%
63%
Return points won·Even
36%
36%
Break points saved·Even
60%
60%
Aces / match·Even
4.7
4.4
Double faults / match·Dominant
3.5
1.4
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Clutch
Under pressureClutch Rating·Slight edge
19
12
Break points saved·Slight edge
77
70
Break points won·Slight edge
20
9
Deciding sets·Slight edge
28
18
Tiebreaks·Clear edge
26
48
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Conditions
Court speed
Fastbig serves, short points
SlowFast