Andres Molteni vs Leonel Alberti — Bolivia F1 Round of 16
Bolivia F1 · ITF · Round of 16
2 — 0
Sets
Monday, 10 September 2007 ·
clay
ARGLeonel Alberti
Last 10 · pre-match
LLLLLLLLLL
Molteni A.6-3 6-1
Alberti L.
Molteni A.
662
Alberti L.
310
Andres Molteni defeated Leonel Alberti 6-3 6-1 in the Bolivia F1 round of 16 on clay. The upset overturned the form book — Leonel Alberti came in leading the head-to-head 1–0, but Andres Molteni had been the form player, winning 2 of their last 10 on clay. Andres Molteni claimed a first win over Leonel Alberti in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Andres Molteni dropped just 4 games past Leonel Alberti.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-09-18 | Bolivia F2 | R32 | clay | Leonel Alberti | 7-6(4) 0-6 7-6(7) |
Statistics
This seasonMolteni A.Alberti L.
1st serve in·
60%
—
1st serve points won·
67%
—
2nd serve points won·
48%
—
Service points won·
59%
—
Return points won·
39%
—
Break points saved·
56%
—
Aces / match·
2.0
—
Double faults / match·
3.3
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.