Pavel Katliarov vs Pavel Chekhov — Belarus F3 Round of 16
Belarus F3 · ITF · Round of 16
2 — 1
Sets
Monday, 11 June 2007 ·
clay
Katliarov P.6-3 6-7 6-4
Chekhov P.
Katliarov P.
66162
Chekhov P.
37741
Pavel Katliarov defeated Pavel Chekhov 6-3 6-7 6-4 in the Belarus F3 round of 16 on clay. The upset overturned the form book — Pavel Chekhov came in leading the head-to-head 2–0, but Pavel Katliarov had been the form player, winning 2 of their last 6 on clay. Pavel Katliarov claimed a first win over Pavel Chekhov in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Pavel Katliarov closed it out in three sets, 6–3 6–7 6–4.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2008-10-20 | Nigeria F4 | R32 | hard | Pavel Chekhov | 6-2 6-3 |
| 2007-05-28 | Ukraine F1 | R32 | clay | Pavel Chekhov | 6-2 7-6(4) |
Statistics
This season1st serve in·
—
63%
1st serve points won·
—
89%
2nd serve points won·
—
38%
Service points won·
—
70%
Return points won·
—
27%
Break points saved·
—
67%
Aces / match·
—
14.0
Double faults / match·
—
3.0
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.