Tatiana Golovin vs Nadia Petrova — Amelia Island Final
Amelia Island · WTA · Final
2 — 0
Sets
Monday, 2 April 2007 ·
clay
Golovin T.6-2 6-1
Petrova N.
Golovin T.
662
Petrova N.
210
Tatiana Golovin defeated Nadia Petrova 6-2 6-1 in the Amelia Island final on clay. The result followed the form book — Tatiana Golovin came in leading the head-to-head 4–1. Tatiana Golovin extended the head-to-head to 5–1.
Key context
- Match story: Tatiana Golovin dropped just 3 games past Nadia Petrova.
Head to head
4–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-03-05 | Indian Wells | R16 | hard | Tatiana Golovin | 6-2 1-0 |
| 2006-10-02 | Stuttgart | F | clay | Nadia Petrova | 6-3 7-6 |
| 2006-08-28 | US Open | R32 | hard | Tatiana Golovin | 7-5 6-7 6-3 |
| 2006-02-06 | Paris | QF | carpet | Tatiana Golovin | 3-6 7-6 6-3 |
| 2005-04-11 | Charleston | QF | clay | Tatiana Golovin | 7-5 6-3 |
Statistics
This season1st serve in·Slight edge
64%
57%
1st serve points won·Even
65%
69%
2nd serve points won·Even
46%
46%
Service points won·Even
58%
59%
Return points won·Even
47%
43%
Break points saved·Even
59%
56%
Aces / match·Clear edge
2.9
5.8
Double faults / match·Even
3.0
3.2
Averages over each player's completed matches in the selected window (57 vs 200). ATP, WTA & Challenger.
Clutch
Under pressureClutch Rating·Slight edge
58
68
Break points saved·Even
64
63
Break points won·Clear edge
72
85
Deciding sets·Clear edge
59
80
Tiebreaks·Clear edge
66
54
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About