Yannick Mertens vs Amir Weintraub — Israel F3 Round of 16
Israel F3 · ITF · Round of 16
2 — 0
Sets
Monday, 19 March 2007 ·
hard
Mertens Y.6-3 6-4
Weintraub A.
Mertens Y.
662
Weintraub A.
340
Yannick Mertens defeated Amir Weintraub 6-3 6-4 in the Israel F3 round of 16 on hard. The upset overturned the form book — Amir Weintraub came in leading the head-to-head 1–0. Yannick Mertens claimed a first win over Amir Weintraub in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Yannick Mertens closed it out in two sets, 6–3 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-12-04 | Israel F6 | R32 | hard | Amir Weintraub | 4-6 7-6(2) 6-2 |
Statistics
This season1st serve in·Even
65%
66%
1st serve points won·Even
68%
67%
2nd serve points won·Even
51%
50%
Service points won·Even
62%
61%
Return points won·Even
39%
38%
Break points saved·Even
59%
57%
Aces / match·Even
2.7
3.3
Double faults / match·Clear edge
2.8
1.8
Averages over each player's completed matches in the selected window (200 vs 118). ATP, WTA & Challenger.