Amir Weintraub vs Yannick Mertens — Israel F6 Round of 32
Israel F6 · ITF · Round of 32
2 — 1
Sets
Monday, 4 December 2006 ·
hard
Weintraub A.4-6 7-6 6-2
Mertens Y.
Weintraub A.
47762
Mertens Y.
66221
Amir Weintraub defeated Yannick Mertens 4-6 7-6 6-2 in the Israel F6 round of 32 on hard. The upset overturned the form book — Yannick Mertens came in leading the head-to-head 1–0. Amir Weintraub claimed a first win over Yannick Mertens in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Amir Weintraub dropped the opening set before beating Yannick Mertens 4–6 7–6 6–2.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-03-19 | Israel F3 | R16 | hard | Yannick Mertens | 6-3 6-4 |
Statistics
This season1st serve in·Even
66%
65%
1st serve points won·Even
67%
68%
2nd serve points won·Even
50%
51%
Service points won·Even
61%
62%
Return points won·Even
38%
39%
Break points saved·Even
57%
59%
Aces / match·Even
3.3
2.7
Double faults / match·Clear edge
1.8
2.8
Averages over each player's completed matches in the selected window (118 vs 200). ATP, WTA & Challenger.