Andrei Mlendea vs Teodor Bolanu — Romania F17 Qualifying Round
Romania F17 · ITF · Qualifying Round
ROUAndrei Mlendea
Last 10 · pre-match
LWLWWWWLWL
2 — 0
Sets
Monday, 21 August 2006 ·
clay
ROUTeodor Bolanu
Last 10 · pre-match
LLLLLLLLLL
Mlendea A.6-2 6-2
Bolanu T.
Mlendea A.
662
Bolanu T.
220
Andrei Mlendea defeated Teodor Bolanu 6-2 6-2 in the Romania F17 qualifying round on clay. The result followed the form book — Andrei Mlendea came in leading the head-to-head 2–0. Andrei Mlendea extended the head-to-head to 3–0.
Key context
- Match story: Andrei Mlendea dropped just 4 games past Teodor Bolanu.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-08-29 | Romania F18 | R16 | clay | Andrei Mlendea | 7-5 6-4 |
| 2005-08-22 | Romania F17 | R32 | clay | Andrei Mlendea | 4-6 6-4 6-0 |