Teodor Bolanu vs Jordane Doble — Romania F17 Round of 16
Romania F17 · ITF · Round of 16
ROUTeodor Bolanu
Last 10 · pre-match
LLLLLLLLLL
2 — 1
Sets
Monday, 21 August 2006 ·
clay
FRAJordane Doble
Last 10 · pre-match
LWLWWWWLLW
Bolanu T.6-3 0-6 6-3
Doble J.
Bolanu T.
6062
Doble J.
3631
Teodor Bolanu defeated Jordane Doble 6-3 0-6 6-3 in the Romania F17 round of 16 on clay. The upset overturned the form book — Jordane Doble came in leading the head-to-head 1–0. Teodor Bolanu claimed a first win over Jordane Doble in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Teodor Bolanu closed it out in three sets, 6–3 0–6 6–3.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-05-01 | Romania F1 | R32 | clay | Jordane Doble | 6-3 6-2 |