Bogdan Leonte vs Teodor BolanuRomania F16 Round of 32

Romania F16 · ITF · Round of 32
ROU
Bogdan Leonte
Last 10 · pre-match
LLLLLLWWWL
2 — 1
Sets
Monday, 14 August 2006 ·
clay
ROU
Teodor Bolanu
Last 10 · pre-match
LLLLLLLLLL
Leonte B.
6-3 5-7 6-2
Bolanu T.
Leonte B.
6562
Bolanu T.
3721

Bogdan Leonte defeated Teodor Bolanu 6-3 5-7 6-2 in the Romania F16 round of 32 on clay. The upset overturned the form book — Teodor Bolanu came in leading the head-to-head 1–0, but Bogdan Leonte had been the form player, winning 3 of their last 9 on clay. Bogdan Leonte claimed a first win over Teodor Bolanu in two meetings, narrowing the head-to-head to 1–1.

Key context

  • Match story: Bogdan Leonte closed it out in three sets, 6–3 5–7 6–2.

Head to head

01
DateTournamentRoundSurfaceWinnerScore
2006-07-17Romania F12R16clayTeodor Bolanu6-3 6-4

Draw