Teodor Bolanu vs Bogdan Leonte — Romania F12 Round of 16
Romania F12 · ITF · Round of 16
ROUTeodor Bolanu
Last 10 · pre-match
LLLLLLLLLL
2 — 0
Sets
Monday, 17 July 2006 ·
clay
ROUBogdan Leonte
Last 10 · pre-match
LLLLLLWWWL
Bolanu T.6-3 6-4
Leonte B.
Bolanu T.
662
Leonte B.
340
Teodor Bolanu defeated Bogdan Leonte 6-3 6-4 in the Romania F12 round of 16 on clay. The upset overturned the form book — Bogdan Leonte came in leading the head-to-head 1–0. Teodor Bolanu claimed a first win over Bogdan Leonte in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Teodor Bolanu closed it out in two sets, 6–3 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-08-14 | Romania F16 | R32 | clay | Bogdan Leonte | 6-3 5-7 6-2 |