Rogerio Dutra Silva vs Andre Miele — Brazil F3 Round of 16
Brazil F3 · ITF · Round of 16
2 — 0
Sets
Monday, 29 May 2006 ·
clay
Dutra Silva R.6-2 7-5
Miele A.
Dutra Silva R.
672
Miele A.
250
Rogerio Dutra Silva defeated Andre Miele 6-2 7-5 in the Brazil F3 round of 16 on clay. The result followed the form book — Rogerio Dutra Silva came in leading the head-to-head 3–0. Rogerio Dutra Silva extended the head-to-head to 4–0.
Key context
- Match story: Rogerio Dutra Silva closed it out in two sets, 6–2 7–5.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-07-19 | Brazil F16 | QF | clay | Rogerio Dutra Silva | 6-3 6-1 |
| 2008-05-05 | Brazil F3 | F | clay | Rogerio Dutra Silva | 5-7 6-2 6-4 |
| 2004-11-15 | Brazil F14 | QF | clay | Rogerio Dutra Silva | 6-2 6-2 |
Statistics
This season1st serve in·Slight edge
61%
67%
1st serve points won·Even
68%
64%
2nd serve points won·Even
51%
50%
Service points won·Even
62%
59%
Return points won·Even
41%
41%
Break points saved·Even
58%
56%
Aces / match·Clear edge
3.2
1.7
Double faults / match·Slight edge
2.7
2.2
Averages over each player's completed matches in the selected window (200 vs 64). ATP, WTA & Challenger.