Jordane Doble defeated Teodor Bolanu 6-3 6-2 in the Romania F1 round of 32 on clay. The upset overturned the form book — Teodor Bolanu came in leading the head-to-head 1–0, but Jordane Doble had been the form player, winning 5 of their last 9 on clay. Jordane Doble claimed a first win over Teodor Bolanu in two meetings, narrowing the head-to-head to 1–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-08-21 | Romania F17 | R16 | clay | Teodor Bolanu | 6-3 0-6 6-3 |