Alexandros Jakupovic vs Stian Boretti — Australia F4 Qualifying Round
Australia F4 · ITF · Qualifying Round
2 — 1
Sets
Monday, 20 March 2006 ·
clay
Jakupovic A.6-4 2-6 6-2
Boretti S.
Jakupovic A.
6262
Boretti S.
4621
Alexandros Jakupovic defeated Stian Boretti 6-4 2-6 6-2 in the Australia F4 qualifying round on clay. The upset overturned the form book — Stian Boretti came in leading the head-to-head 1–0. Alexandros Jakupovic claimed a first win over Stian Boretti in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Alexandros Jakupovic closed it out in three sets, 6–4 2–6 6–2.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-03-13 | Australia F3 | R16 | clay | Stian Boretti | 6-2 6-0 |