Gisela Dulko vs Stephanie Cohen Aloro — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 0
Sets
Monday, 6 March 2006 ·
hard
Dulko G.7-6 6-1
Cohen Aloro S.
Dulko G.
762
Cohen Aloro S.
610
Gisela Dulko defeated Stephanie Cohen Aloro 7-6 6-1 in the Indian Wells round of 64 on hard. The upset overturned the form book — Stephanie Cohen Aloro came in leading the head-to-head 1–0. Gisela Dulko claimed a first win over Stephanie Cohen Aloro in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Gisela Dulko came through a tight passage before pulling clear — 7–6 6–1.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2009-05-18 | Strasbourg | R16 | clay | Stephanie Cohen Aloro | 4-6 7-6 6-4 |
Statistics
This season1st serve in·Even
60%
60%
1st serve points won·Even
61%
62%
2nd serve points won·Even
45%
41%
Service points won·Even
55%
54%
Return points won·Even
45%
42%
Break points saved·Even
54%
55%
Aces / match·Even
1.9
1.9
Double faults / match·Clear edge
4.1
5.0
Averages over each player's completed matches in the selected window (200 vs 37). ATP, WTA & Challenger.
Clutch
Under pressureClutch Rating·Even
48
46
Break points saved·Clear edge
34
55
Break points won·Slight edge
74
63
Deciding sets·Clear edge
69
49
Tiebreaks·Slight edge
48
57
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Conditions
Court speed
Medium-slowfavours grinders
SlowFast