Andrei Stoliarov vs Derek Klemish — Romania F7 Round of 16
Romania F7 · ITF · Round of 16
2 — 0
Sets
Monday, 13 June 2005 ·
clay
USADerek Klemish
Last 10 · pre-match
LLW
Stoliarov A.6-2 6-0
Klemish D.
Stoliarov A.
662
Klemish D.
200
Andrei Stoliarov defeated Derek Klemish 6-2 6-0 in the Romania F7 round of 16 on clay. The result followed the form book — Andrei Stoliarov came in leading the head-to-head 1–0. Andrei Stoliarov extended the head-to-head to 2–0.
Key context
- Match story: Andrei Stoliarov handed Derek Klemish a second-set bagel in a 6–2 6–0 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-06-20 | Romania F8 | R32 | clay | Andrei Stoliarov | 6-0 6-0 |