Svetlana Kuznetsova vs Jessica Kirkland — Australian Open Round of 128
Australian Open · WTA · Round of 128
2 — 0
Sets
Monday, 17 January 2005 ·
hard
Kuznetsova S.6-1 6-1
Kirkland J.
Kuznetsova S.
662
Kirkland J.
110
Svetlana Kuznetsova defeated Jessica Kirkland 6-1 6-1 in the Australian Open round of 128 on hard. The result followed the form book — Svetlana Kuznetsova came in leading the head-to-head 1–0, defending last year's round of 32. Svetlana Kuznetsova extended the head-to-head to 2–0.
Key context
- Match story: Svetlana Kuznetsova dropped just 2 games past Jessica Kirkland.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-03-05 | Indian Wells | R128 | hard | Svetlana Kuznetsova | 6-3 6-0 |
Statistics
This season1st serve in·Slight edge
66%
59%
1st serve points won·Even
64%
64%
2nd serve points won·Even
45%
43%
Service points won·Even
57%
55%
Return points won·Slight edge
45%
40%
Break points saved·Clear edge
55%
70%
Aces / match·Even
2.9
2.8
Double faults / match·Dominant
3.2
7.0
Averages over each player's completed matches in the selected window (197 vs 4). ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast