Teodor Bolanu vs Bogdan Nitescu — Romania F6 Round of 32
Romania F6 · ITF · Round of 32
ROUTeodor Bolanu
Last 10 · pre-match
LLLLLLLLLL
2 — 0
Sets
Monday, 28 July 2003 ·
clay
ROUBogdan Nitescu
Last 10 · pre-match
LLWLLL
Bolanu T.6-3 6-4
Nitescu B.
Bolanu T.
662
Nitescu B.
340
Teodor Bolanu defeated Bogdan Nitescu 6-3 6-4 in the Romania F6 round of 32 on clay.
Key context
- Match story: Teodor Bolanu closed it out in two sets, 6–3 6–4.
Head to head
No previous meetings on record.